d is a point on the side bc of a triangle

D is a0:02:23

D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC | Exercise 6.3 class 10 Q13

D is a0:01:28

D is a point on the side BC of a triangle ABC such that `/_A D C=/_B A C` . Show that `C A^2=C B...

Ex6.3,QNo13, D is0:02:27

Ex6.3,QNo13, D is a point on side BC of ΔABC such that angle ADC= BAC, show that CA^2=CB.CD, triang

D is a0:07:08

D is a point on the side BC of a triangle ABC such that angle ADC =angle BAC show that CA²=CB.CD

D is a0:03:13

D is a point on the side BC of a ∆ABC such that ∠ADC=∠BAC show that CA^2=CB.CD | TRIANGLE[GEOMETRY]

In the given0:03:10

In the given figure, D is a point on side BC of a `DeltaABC` and E is a point such that CD = DE.

\( D \)0:05:23

\( D \) is a point on the side \( B C \) of a \( \triangle A B C \) such that \( A D \) bisects ...

D is the0:06:08

D is the midpoint of side BC of a triangle ABC AD is bisected

Class 10 |0:57:50

Class 10 | Mathematics | Class-02 | Unit 09 | Some Application of Trigonometry | TTT Academy

In Triangle ABC0:01:36

In Triangle ABC D is a point on side BC.Such that ADC =BAC.If CA=15cm and CD=9cm then CB=

In the figure,0:06:12

In the figure, in triangle ABC, point D on side BC is such that, angle BAC = angle ADC. Prove that

D is a0:04:29

D is a point on the side BC of a triangle ABC such that ∠ADC = ∠ BAC. Show that CA2 = CB.CD

In fig.9, `D`0:01:40

In fig.9, `D` is a point on side `B C` of a `\\ A B Cdot\\ \\ A D` is joined. Name all the trian...

Let O be0:01:55

Let O be the in-centre of a triangle ABC and D be a point on theside BC of ΔABC, such that OD

Ques 13.D is0:02:02

Ques 13.D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD.

In △ABC, D0:04:22

In △ABC, D is point on side BC such that ∠ADC = ∠BAC. If CA = 12 cm, CD = 8 cm, then CB (in cm) = ?

D is a0:03:29

D is a point on the side BC of a triangle ABC such that `/_A D C=/_B A C` . Show that `C A^2=C B...

D is a0:02:39

D is a point on the side BC of a triangle ABC such that angle ADC =angle BAC.Show that CA²=CB.CD

D is the0:05:47

D is the mid-point of side BC at a triangle ABC.AD is bisected at the point E and

A point D0:01:51

A point D is taken from the side BC of a right-angled triangle ABC,where AB is hypotenuse. Then

D is the0:09:04

D is the mid-point of side BC of a ∆ABC. AD is bisected at the point E and BE produced cuts AC at th

5. D is0:02:28

5. D is a point on the side BC of a ∆ABC such that ∠ADC = ∠BAC. If CA = 10cm and BC = || edu214

IX Lines and0:05:00

IX Lines and Angles In the given figure, the side BC of triangle ABC has been produced to a point D

D is a0:05:49

D is a point on the side B C of a triangle ABC such that ∠ADC=∠BAC. Show that CA^2=CB·CD.